网站首页/技术开发列表/内容

我有一个加密办法,欢迎大家指正

技术开发2022-08-02阅读

<%
IF Request("Action")=1 then
Dim String,StringLen,i,StringNumTmp,StringRndNum,ResultString,j
String = Request("Pass")            '密码字符串

'开始计算字符数据
StringLen = Len(String)

For i = 1 to StringLen

  StringNumTmp = Asc(Mid(String,i,1))
  
  Randomize
  StringRndNum=Int((18-1)*Rnd+1)
  
  if Len(StringNumTmp + StringRndNum) < 3 then
  
  For j = 1 to 3 - Int(Len(StringNumTmp + StringRndNum))
    StringNumber = "0" & (StringNumTmp + StringRndNum)
  Next
  
  Else
  
    StringNumber = StringNumTmp + StringRndNum
  
  End if
  
  ResultString = ResultString & Chr(StringNumTmp - StringRndNum) & StringNumber

Next

Response.write "加密后结果:" & ResultString            '输出结果

%>
<BR>
<%
'开始破解

For i = 1 to Len(ResultString) Step 4

  PString = Left(Mid(ResultString,i,4),1)
  
  PStringNum1 = Asc(PString)
  
  PStringNum2 = Int(Right(Mid(ResultString,i,4),3))
  
  PStringNum = (PStringNum1 + PStringNum2) / 2
  
  PString1 = PString1 & Chr(PStringNum)

Next

Response.write "破解后结果:" & PString1
End if
%>
<Form method="post" action="ttt.asp?action=1">
<input type=password name="pass" size=15><input type=submit>
</form>

……

相关阅读